$\dot{Q} {net}=\dot{Q} {conv}+\dot{Q} {rad}+\dot{Q} {evap}$
Solution:
$h=\frac{Nu_{D}k}{D}=\frac{10 \times 0.025}{0.004}=62.5W/m^{2}K$
$T_{c}=T_{s}+\frac{P}{4\pi kL}$
The heat transfer due to conduction through inhaled air is given by:
$\dot{Q} {net}=\dot{Q} {conv}+\dot{Q} {rad}+\dot{Q} {evap}$
Solution:
$h=\frac{Nu_{D}k}{D}=\frac{10 \times 0.025}{0.004}=62.5W/m^{2}K$
$T_{c}=T_{s}+\frac{P}{4\pi kL}$
The heat transfer due to conduction through inhaled air is given by: