return True
for i, j in zip(range(row, n, 1), range(col, -1, -1)): if board[i][j] == 1: return False
def solve_n_queens(n): def can_place(board, row, col): for i in range(col): if board[row][i] == 1: return False
The solution to the Queen of Enko Fix can be implemented using a variety of programming languages. Here is an example implementation in Python:
def place_queens(board, col): if col >= n: result.append(board[:]) return
result = [] board = [[0]*n for _ in range(n)] place_queens(board, 0) return [["".join(["Q" if cell else "." for cell in row]) for row in sol] for sol in result]
return True
for i, j in zip(range(row, n, 1), range(col, -1, -1)): if board[i][j] == 1: return False
def solve_n_queens(n): def can_place(board, row, col): for i in range(col): if board[row][i] == 1: return False
The solution to the Queen of Enko Fix can be implemented using a variety of programming languages. Here is an example implementation in Python:
def place_queens(board, col): if col >= n: result.append(board[:]) return
result = [] board = [[0]*n for _ in range(n)] place_queens(board, 0) return [["".join(["Q" if cell else "." for cell in row]) for row in sol] for sol in result]